cosθ - sin / 1
θ + 2 tanθ
=
11
∣ 2
∣ 10 J
(a) 1 -
1
θ
2
-
1
θ + 2θ ”
11
2 2 10
M1 1.2
A1 1.1b
⟶
1
2
θ
2
-
3
2
θ
+
1
1
0
”0 ⟶
5θ
2
- 15θ + 1 ”0 * A1* 2.1
(3)
(b) θ =0.068 is valid because θ is small
θ =2.932 is not valid because θ is large
B1 2.3
(1)
(4 marks)
Question 1 Notes:
(a)
At least two of either cosθ ”1 -
1
θ
2
, sin / 1
θ 1
θ or tanθ ”θ
substituted into the given
2
∣ 2
∣
”
J 2
equation
Substitutes cosθ ”1 -
1
θ
2
, sin / 1
θ
1
θ and tanθ ”θ into the given
equation to obtain a
2
∣ 2
∣
”
J 2
correct (un-simplified) approximation or equation. E.g. 1 -
1
θ
2
-
1
θ +
2θ ”
11
or =
11
2 2 10 10
Obtains 5θ
2 - 15θ + 1 ”0 (condone 5θ
2 - 15θ + 1 =0 ) with no errors
seen in their working
States θ =0.068 is valid because θ is small; and θ =2.932 is not valid
because θ is large
M1:
A1:
A1*:
(b)
B1:
(b)
Alt
1
B1:
LHS =cosθ - sin / 1
θ + 2 tanθ
∣ 2
∣
J
States θ =0.068 is valid and θ =2.932 is not valid based on testing
these two values in the original equation
Note: θ =0.068 ⟶ LHS =1.0999... & θ =2.932 ⟶ LHS =- 2.3980...
Note: θ =0.068218... ⟶ LHS =1.1002... & θ =2.931782... ⟶ LHS =-
2.3984..
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